(2+3x^2)=19/4*x

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Solution for (2+3x^2)=19/4*x equation: 



(2+3x^2)=19/4x

We move all terms to the left:

(2+3x^2)-(19/4x)=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(2+3x^2)-(+19/4x)=0

We get rid of parentheses

3x^2-19/4x+2=0

We multiply all the terms by the denominator


3x^2*4x+2*4x-19=0

Wy multiply elements

12x^3+8x-19=0

We do not support expression: x^3

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